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[jQuery] create table ID's from index

in Using jQuery • 13 years ago

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body bgcolor="#ffffff" text="#000066">
<font face="Trebuchet MS"><font face="Arial"><small>have about 150 html
tables ( all same format, headings etc). Trying to assign ID's based on
fact they all carry appropriate name in same td index in table.
not heavily versed in JS and closest I've come is
$("table").each(function(i){
               var country_name= $("this tr:eq(1) td:eq(1)
").html();
                this.id = country_name +this.id + i;
        });
I can get the country_name to write to an alert however am having
trouble getting it to work with index. Tried a variety of things ( swap
html() fo rval(), tried $.merge etc
my outputs to the ID's are working but I either get "undefined with
index# or put various bracket on the var and it come out as text
instead of it's value
I don't have the server side experience to do this through php/sql etc
and am really close now with it
any help greatly appreciated
</small>
</font></font>
</body>
</html>

Replies(5)

michaelli..

Re: [jQuery] create table ID's from index

13 years ago

If I read you right, you're trying to assign an ID to the table and it
doesn't already have one? If that's the case, you reference the
table's id in:
this.id = country_name +this.id + i;
so unless the table already has an id, the second this.id will be
undefined.

charlietfl

Re: [jQuery] create table ID's from index

13 years ago

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body bgcolor="#ffffff" text="#000066">
where it stands now, tables have no id's however if i put the variable
I'm taking from a td and write it as "country_name" + this.id +i it
produces the variable name (not value) with index and tables get
id's country_name1, country_name2, etc
if i remove brackets from country name I get undefined1, undefined2 etc
for the ID's
the this.id is working fine, problem is getting my text out of the td
to work , the index is working fine
mkmanning wrote:
<blockquote
id="mid_8b68115f-3010-4718-8475-8bde2aea091b_l33g2000pri_googlegroups_com"
cite="mid:8b68115f-3010-4718-8475-8bde2aea091b@l33g2000pri.googlegroups.com"
type="cite">
<pre wrap="">If I read you right, you're trying to assign an ID to the table and it
doesn't already have one? If that's the case, you reference the
table's id in:
this.id = country_name +this.id + i;
so unless the table already has an id, the second this.id will be
undefined.

michaelli..

Re: [jQuery] create table ID's from index

13 years ago

Sorry, didn't look closely enough. Your selector is wrong; try this:
var country_name= $("td:first",this).text();

charlietfl

Re: [jQuery] create table ID's from index

13 years ago

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
</head>
<body bgcolor="#ffffff" text="#000066">
<pre wrap="">oddly enough that is the one option that doesn't produce anything ...no firebug errors and no output
with selector ending in html() i can print alerts with the cell contents, just can't get the variable and the index to create one output
selector tried ...tr alone... then tr td, ....tr td text tried them all with .val(), .text() and .html()
tried the this function with a variety of configs also
i seem to be close but my strengths are not in scripting
</pre>
mkmanning wrote:
<blockquote
id="mid_31c66d43-5717-418b-a588-ee326233fe14_e36g2000prg_googlegroups_com"
cite="mid:31c66d43-5717-418b-a588-ee326233fe14@e36g2000prg.googlegroups.com"
type="cite">
<pre wrap="">Sorry, didn't look closely enough. Your selector is wrong; try this:
var country_name= $("td:first",this).text();

michaelli..

Re: [jQuery] create table ID's from index

13 years ago

Given this table:
<table>
<tr><td>test</td></tr>
<tr><td>etc</td></tr>
</table>
This JavaScript:
$("table").each(function(i){
var country_name= $("td:first",this).html();
this.id = country_name +this.id + i;
console.log(country_name +this.id + i);
});
Produces this output in the console, as expected:
test0
It might be valuable at this point for you to post the markup for the
table you are using.

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