jQuery Forum

Here's the call for the busy indicator and the long running process in the call back

1. ShowBusyIndicator(null, true, null, function () {
       if ($('#AddEditForm').length == 0)
           CreateAddEditForm(null, function() {
                   $(this).remove();
               });
       else {
           RemoveBusyIndicator();
           $('#AddEditForm').show('slow');
       }
   });
   

It still doesn't work.  To answer your question I was trying to make sure that the Busy Indicator be really on the DOM and visible before doing anything else.

Here's the modified code according to your idea :

1. function AddNewRow() {
       ShowBusyIndicator(null, true, 'black');
2.     setTimeout(function () {
           if ($('#AddEditForm').length == 0)
               CreateAddEditForm(null, function () {
                   $(this).remove();
               });
           else {
               RemoveBusyIndicator();
               $('#AddEditForm').show('slow');
           }
       });
   }
   

Ok the setTimeout seems to work if I set something else than 0 from your example if I set 500 it works